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Hi all,
I am sorry for this vendor-specific question, but I really hope that someone can help me out here.
Using C# in .NET, I have an aspx file with an Xml control (Xml1). I try to pass a nodeset as a parameter to the xsl file
that transform the xml document (oXmlDoc). This is not succesful. Can someone tell me what I am doing wrong, and how I am
able to pass a nodelist to the stylesheet?
Thanks in advance!
C# code snippet:
System.Xml.XmlDocument oXmlDoc = new System.Xml.XmlDocument();
oXmlDoc.LoadXml(sXml); // sXml is the string containing the XML
System.Xml.XmlNodeList oList = oXmlDoc.SelectNodes("/Root/Elem[@ID='1' or @ID='3' or @ID='4']");
System.Xml.Xsl.XsltArgumentList args = new System.Xml.Xsl.XsltArgumentList();
args.AddParam("TestList", "", oList);
Stylesheet (Transform.xsl):
<?xml version="1.0" encoding="ISO-8859-1">
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" encoding="ISO-8859-1" indent="no"/>
<xsl:param name="TestList"/>
Output:
The data in the table is not important here. What is important is that I wanted the variable $TestList to contain a list of Elem nodes (those with ID one of 1,3,4) but instead it contains: System.Xml.XPath.XPathNodeList.
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[xsl] Nodelist as input parameter to XSL stylesheet in .NET
|
Subject: [xsl] Nodelist as input parameter to XSL stylesheet in .NET From: "Ragulf Pickaxe" <jawxml@xxxxxxxxxxx> Date: Wed, 22 Sep 2004 11:36:26 +0000 |
Hi all,
I am sorry for this vendor-specific question, but I really hope that someone can help me out here.
Using C# in .NET, I have an aspx file with an Xml control (Xml1). I try to pass a nodeset as a parameter to the xsl file
that transform the xml document (oXmlDoc). This is not succesful. Can someone tell me what I am doing wrong, and how I am
able to pass a nodelist to the stylesheet?
Thanks in advance!
Regards, Ragulf Pickaxe :-)
C# code snippet:
System.Xml.XmlDocument oXmlDoc = new System.Xml.XmlDocument();
oXmlDoc.LoadXml(sXml); // sXml is the string containing the XML
System.Xml.XmlNodeList oList = oXmlDoc.SelectNodes("/Root/Elem[@ID='1' or @ID='3' or @ID='4']");
System.Xml.Xsl.XsltArgumentList args = new System.Xml.Xsl.XsltArgumentList();
args.AddParam("TestList", "", oList);
Xml1.TransformArgumentList = args; Xml1.TransformSource = "Transform.xsl"; Xml1.Document=oXmlDoc;
input xml (oXmlDoc): <?xml version="1.0"?> <Root> <Elem ID="1">Number 1</Elem> <Elem ID="2">Number 2</Elem> <Elem ID="3">Number 3</Elem> <Elem ID="4">Number 4</Elem> <Elem ID="5">Number 5</Elem> <Elem ID="6">Number 6</Elem> </Root>
Stylesheet (Transform.xsl):
<?xml version="1.0" encoding="ISO-8859-1">
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" encoding="ISO-8859-1" indent="no"/>
<xsl:param name="TestList"/>
<xsl:template match="/">
<HTML><BODY>
TestList: <xsl:copy-of select="$TestList"/><br/>
<xsl:apply-templates select="Root"/>
</BODY></HTML>
</xsl:template> <xsl:template match="Root">
<table>
<xsl:apply-templates select="Elem"/>
</table>
</xsl:template> <xsl:template match="Elem">
<tr><td>
<xsl:value-of select="."/>
</td></tr>
</xsl:template>
</xsl:stylesheet>Output:
TestList: System.Xml.XPath.XPathNodeList Number 1 Number 2 Number 3 Number 4 Number 5 Number 6
The data in the table is not important here. What is important is that I wanted the variable $TestList to contain a list of Elem nodes (those with ID one of 1,3,4) but instead it contains: System.Xml.XPath.XPathNodeList.
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