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[xsl] XSLT Doctype and XHTML output
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Subject: [xsl] XSLT Doctype and XHTML output From: karl@xxxxxxxxxxxxxxxxxxxx Date: Wed, 8 Sep 2004 15:13:54 -0600 (CST) |
First: The doctype I am trying to use looks like this: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> I don't know how to get the Doctype to look like this in XSLT - current form is: <xsl:output Method="html" encoding="UTF-8" doctype-public="-//W3C//DTD XHTML 1.0 Transitional//EN" /> I don't know where to add: "http://www.w3.org/TR/html4/strict.dtd" to the above. Second: I am now using the ADODB Stream method to stream the result of the transformation correctly and then perform an response.binarywrite. However, lets say I'm interested in XHTML results so I add the following namespace decleration to the stylesheet: xmlns="http://www.w3.org/1999/xhtml" The encoding I specified in the xsl:output gets lost is this normal? Third: This is illegal? (Doctype decleration in top-level node match) <xsl:template match="/"> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"/> (again, this is the doctype form I am trying to achieve) Thanks, Karl
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