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This is a kind of generalised way you can solve this.
You must some how have in the XML of the page, the pageid of the current page.
like page-id = 1
or page-id = 2..
now.
Decide how many results go into each page.. based on your favourite algorithm..or may be a standard value.
so you have tha max results per page. and you have the start index which is 1.
now run a for-each select = "results[position() >=$start-index and position() <=$max-per-page]">
this will limit your search results...
now continue doing this for the nextpage and so on.. where the start-index and max-per page keep changing based on the page id.
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RE: [xsl] limit number of row return by xslt
Subject: RE: [xsl] limit number of row return by xslt From: "Vasu Chakkera" <vasucv@xxxxxxxxxxx> Date: Sun, 22 Aug 2004 13:32:28 +0000 |
This is a kind of generalised way you can solve this.
You must some how have in the XML of the page, the pageid of the current page.
like page-id = 1
or page-id = 2..
now.
Decide how many results go into each page.. based on your favourite algorithm..or may be a standard value.
so you have tha max results per page. and you have the start index which is 1.
now run a for-each select = "results[position() >=$start-index and position() <=$max-per-page]">
this will limit your search results...
now continue doing this for the nextpage and so on.. where the start-index and max-per page keep changing based on the page id.
Hope this helps Vasu
From: Tham Tinh <khautinh@xxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: XSL List <XSL-List@xxxxxxxxxxxxxxxxxxxxxx> Subject: [xsl] limit number of row return by xslt Date: Fri, 20 Aug 2004 15:15:01 -0700 (PDT)
Hi all, Thanks for all previous helps and answers. Now I would like to ask how to limit number of row return with xslt. Ex: My return data will be 100 rows, I'd like to return just 20 rows per page and have an option for user to click to view next 20 rows. Please help me again! Thanks
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