RE: [xsl] count the number of descending nodes

Hi,

> i have one xml as this:
> <root>
>  <no>
>   <my>w</my>
>   <my>e</my>
>  </no>
>  <no>
>   <my>p</my>
>  </no>
> </root>
> 
> i want to see if above of the no node there is one or more 
> nodes with the
> name my.
> i make this:
> <xsl:for-each select="/root/no">
> <xsl:choose>
> <xsl:when test="'count(my) =1'">ok</xsl:when>
> <xsl:otherwise>no</xsl:otherwise>
> </xsl:choose>
> </xsl:for-each>
> 
> but it doesn't print well.

What do you mean "print well"? The output is not pretty, or that the results are wrong?

> how can i known if there is one or more nodes child with the mane my?

You can either test it like you do, count the nodes. The more common way is to just try to select the nodes, i.e.

  <xsl:when test="my">ok</xsl:when>

Cheers,

Jarno - Chris C: Plymouth <http://www.hardnrg.com/mixes/chrisc.php>