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At 2004-05-06 15:33 +0200, Dionisio Ruiz de Zarate wrote:
You shouldn't have put the test into single quotes ... a working example is below.
I hope this helps.
................ Ken
T:\>
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Re: [xsl] count the number of descending nodes
Subject: Re: [xsl] count the number of descending nodes From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx> Date: Thu, 06 May 2004 10:06:07 -0400 |
At 2004-05-06 15:33 +0200, Dionisio Ruiz de Zarate wrote:
hello i have one xml as this: ... i want to see if above of the no node there is one or more nodes with the name my. i make this: <xsl:for-each select="/root/no"> <xsl:choose> <xsl:when test="'count(my) =1'">ok</xsl:when>
You shouldn't have put the test into single quotes ... a working example is below.
I hope this helps.
................ Ken
T:\>type dionisio.xml <root> <no> <my>w</my> <my>e</my> </no> <no> <my>p</my> </no> </root>
T:\>type dionisio.xsl <?xml version="1.0" encoding="iso-8859-1"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output indent="yes"/> <xsl:output method="text"/>
<xsl:template match="/"> <xsl:for-each select="/root/no"> <xsl:choose> <xsl:when test="count(my)=1">ok</xsl:when> <xsl:otherwise>no</xsl:otherwise> </xsl:choose> <xsl:text> </xsl:text> </xsl:for-each> </xsl:template>
</xsl:stylesheet> T:\>saxon dionisio.xml dionisio.xsl no ok
T:\>
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