[XSL-LIST Mailing List Archive Home] [By Thread] [By Date]

Re: [xsl] Dynamical work with child nodes

---

---

Hi Roland,
  Something like the following might be ok. The
structure just illustrates the concept.

<xsl:template match="/">
   <xsl:for-each select="root/rowset/row">
     <xsl:for-each select="*">
        <xsl:value-of select="name(.)" /> -
<xsl:value-of select="." />
     </xsl:for-each>
   </xsl:for-each>
</xsl:template>

Regards,
Mukul

 --- Roland Juergens <roland_juergens@xxxxxxxxxxxx>
wrote: > Hi,
> 
> I have an XML file like this which contains results
> from a database query.
> Is there a way to go dynamically through the
> subelements of my "row"
> elements, because I want to use it for different
> queries.
> So the subelements like "id" or "name" might change.
> 
> <root>
> 	<rowset>
> 		<row>
> 			<id>1</id>
> 			<name>bla</name>
> 		</row>
> 		<row>
> 			<id>2</id>
> 			<name>blabla</name>
> 		</row>
> 
> 		...(more <row> elements)...
> 
> 	</rowset>
> </root>
> 
> 
> This is how the xsl-file looks like now
> 
> ...
> <xsl:for-each select="root/rowset/row">
> ...
> 	<xsl:value-of select="id"/>
> ...
> 	<xsl:value-of select="name"/>
> ...
> </xsl:for-each>
> ...
> 
> 
> 
> What I imagine is the following :
> I want to get the number of subelements of a "row"
> element, then iterate
> over it to get the names, and then building it
> dynamical.
> Is something like that possible ?
> 
> 
> Roland Juergens
>  

________________________________________________________________________
Yahoo! India Insurance Special: Be informed on the best policies, services, tools and more. 
Go to: http://in.insurance.yahoo.com/licspecial/index.html

---