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[xsl] Display records in 3 columns

Subject: [xsl] Display records in 3 columns
From: "Peter Lukan" <peter.lukan@xxxxxxxx>
Date: Thu, 1 Apr 2004 12:04:18 +0200


I'm having trouble with displaying data in 3 columns.

I've managed to create a table with 3 columns :

******* XSL code ***********

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

<xsl:output method="html"/>

<xsl:template match="/">
 <table width="400">
 <xsl:call-template name="coloredRow">
  <xsl:with-param name="count" select="1"/>

<xsl:template name="coloredRow">
<xsl:param name="count"/>

<xsl:if test="$count != count(data/objekt)">

  <xsl:if test="1=($count mod 3)">#<#tr#>#</xsl:if>

  <td bgcolor="#ccff66">
    vsebina: <xsl:value-of select="data/objekt/filename"/>

  <xsl:if test="0=($count mod 3)">#<#/tr#>#</xsl:if>
     <xsl:call-template name="coloredRow">
        <xsl:with-param name="count" select="$count + 1"/>



************* end of XSL code **************

but I can't display different records in this code <xsl:value-of
I think I should use position() function but don't know how!

Thanx Peter Lukan

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