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RE: [xsl] Generating HTML table
Subject: RE: [xsl] Generating HTML table From: cknell@xxxxxxxxxx Date: Fri, 05 Mar 2004 09:54:17 -0500 |
Yes, I did one of these a few years ago. You will want to use the modulo operator on the value of the context node's position(). Here's how it's done: <xsl:template match="/"> <table> <xsl:for-each select="items/item"> <xsl:choose> <xsl:when test="position() mod 4 = 1"> <tr> <td><xsl:value-of select="."/></td> <td><xsl:value-of select="following-sibling::*[1]"/></td> <td><xsl:value-of select="following-sibling::*[2]"/></td> <td><xsl:value-of select="following-sibling::*[3]"/></td> </tr> </xsl:when> <xsl:otherwise></xsl:otherwise> </xsl:choose> </xsl:for-each> </table> </xsl:template -- Charles Knell cknell@xxxxxxxxxx - email -----Original Message----- From: Andreas Lindahl <andreas.lindahl@xxxxxxxxxx> Sent: Fri, 5 Mar 2004 13:10:32 +0100 To: "'xsl-list@xxxxxxxxxxxxxxxxxxxxxx'" <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Subject: [xsl] Generating HTML table Hi My XML file looks like this: <items> <item>Item 1</item> <item>Item 2</item> <item>Item 3</item> <item>Item 4</item> <item>Item 5</item> <item>Item 6</item> ... </item> And I would like to create an HTML table which looks like this, from my XML file: <table> <tr> <td> Item 1 Item 5 </td> <td> Item 2 Item 6 </td> <td> Item 3 </td> <td> Item 4 </td> </tr> </table> I.e. four columns which are "populated" with items horisontally. Is this possible to do with XSLT? XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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