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Re: [xsl] Modifying the xPath order...

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What are you wanting to do exacly, i think im missing your question
----- Original Message -----
From: <i92agcad@xxxxxx>
To: "Lista XSL" <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, March 01, 2004 9:32 AM
Subject: [xsl] Modifying the xPath order...



 I have this structure in XML...

 <elements>
  <element>5</element>
  <element>3</element>
  <element>6</element>
  <element>1</element>
 </elements>

 With XSL, i have...

 <xsl:for-each select="element">
  <xsl:sort select="." order="ascending" data-type="number"/>
   ...
 </xsl:for-each>

 In this way, the elements have this order...

 position() = 1 --> element = 1
 position() = 2 --> element = 3
 position() = 3 --> element = 5
 position() = 4 --> element = 6

 But ...

 preceding of element = 1 is element = 6
 preceding of element = 3 is element = 5
 preceding of element = 5 is element = null
 preceding of element = 6 is element = 3

 Then, how i know that preceding of element=3 in the order is the element =
1?
¿?

 How i calculate the acumulated total?¿? (for the element = 5 the total
acumulated is 1 + 3 + 5 ...)

 Thanks!!!





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