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[xsl] Need expression..
Subject: [xsl] Need expression.. From: "Kotes Mogili" <Kotes.Mogili@xxxxxxxxxxxxxxxxx> Date: Tue, 3 Feb 2004 15:03:38 -0500 |
Hi, I want to go to a node directly through XPath expression. For example I need to select AddressLine1 from CutAddress where AddressType='Service'. Currently I am using .//*[AddressType='Service']/AddressLine1. But when I use .//CutAddress[AddressType='Service']/AddressLine1 it is not working.Can anybody correct me?? Thanks Kotes <SiebelMessage MessageId="" MessageType="Integration Object" IntObjectName="Txn 28 IO"> <VitriaDescriptionOut028> <Account> <ListOfAccountSalesInfo> <AccountSalesInfo> <LDLocal>Local</LDLocal> <SalesAgentCode/> <SalesContact/> <SalesSourceCode/> </AccountSalesInfo> <AccountSalesInfo> <LDLocal>LD</LDLocal> <SalesAgentCode/> <SalesContact/> <SalesSourceCode/> </AccountSalesInfo> </ListOfAccountSalesInfo> <ListOfCutAddress> <CutAddress> <AddressLine1>365 HUNTSMILL BLVD</AddressLine1> <AddressLine2/> <AddressName/> <AddressType>Service</AddressType> <City>SCARBOROUGH</City> <PostalCode>M1W2Y9</PostalCode> <State>ON</State> </CutAddress> <CutAddress> <AddressLine1>366 HUNSTMILL BLVD</AddressLine1> <AddressLine2/> <AddressName/> <AddressType>Billing</AddressType> <City>SCARBOROUGH</City> <PostalCode>M1W2Y9</PostalCode> <State>ON</State> </CutAddress> <CutAddress> <AddressLine1>364 HUNTSMILL BLVD</AddressLine1> <AddressLine2/> <AddressName/> <AddressType>Main</AddressType> <City>SCARBOROUGH</City> <PostalCode>M1W2Y9</PostalCode> <State>ON</State> </CutAddress> </ListOfCutAddress> </Account> </VitriaDescriptionOut028> </SiebelMessage> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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