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Re: [xsl] No html if XSD present?


Subject: Re: [xsl] No html if XSD present?
From: Robert Koberg <rob@xxxxxxxxxx>
Date: Tue, 27 Jan 2004 15:49:26 -0800

davidpbrown wrote:

I have an XML source from which I generate xhtml from an XSLT.

That works fine and there's no problem until I suggest a XSD in the XML.
Then it spews out only the text result with none of the tags!?

The only tag to survive is the XML <?xml version="1.0" encoding="utf-8"?>

The XSL, XSD and XML are all valid as per the Sun's Multischema XML
validator (thanks to G. Ken Holman for suggesting that in another post)

The XML's XSD declaration I have as
<file xmlns="http://www.example.com/ns/file.xsd"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.example.com/ns/file.xsd">

I am processing these on my local hard drive but this seems to be ok, in
that the XSD declares that it is the http://www.example.com/ns/file.xsd
suggested, even though it isn't found at that location.

The command line used is
java org.apache.xalan.xslt.Process -in file.xml -xsl file.xsl -out file.html

Any ideas why no tags pass when XSD is present?

Can you set up a transformation (using the same things you describe above, but greatly simplified) that produces something extremely simple, like:


<html><body>boo</body></html>

If you do this, the answer will probably present itself. If it doesn't, then you should post the (simplified!) schema, XML and XSL to the list and the answer will most likely be given to you.

possible hint: your namespaces are getting messed/mixed up.

best,
-Rob


Thanks davidpbrown



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