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RE: [xsl] Get path of xsl template


Subject: RE: [xsl] Get path of xsl template
From: Jarno.Elovirta@xxxxxxxxx
Date: Tue, 20 Jan 2004 12:19:55 +0200

Hi,

> Is there an  xsl function for obtaining the path of an xsl 
> template and then
> parsing that path into its various directory names.

No.
 
> Does anyone please have an example of how to do this.

Pass the information using xsl:param or with an external source tree accessed using document().

Cheers,

Jarno - Wumpscut: Mother (Maternal Instinct)

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