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RE: RE: [xsl] self closing elements with attributes


Subject: RE: RE: [xsl] self closing elements with attributes
From: "Josh Canfield" <josh.canfield@xxxxxxxxxxxx>
Date: Tue, 6 Jan 2004 13:48:37 -0800

You shouldn't need the xsl:output element, when I comment it out I still get correct results.

without the xsl:output you should get:

<foo bar="some foo"/><foo bar="some foo"/><foo bar="some foo">
foo
</foo><foo bar="some foo">
foo
</foo>

-----Original Message-----
From: annirack@xxxxxxx [mailto:annirack@xxxxxxx]
Sent: Tuesday, January 06, 2004 1:15 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: RE: [xsl] self closing elements with attributes


> Hmm... I'm using Xalan 2.5.2 and when I process this template:
 
[snip]
 
> I get:
 
I knocked off the carriage returns in my source, and I got:

<?xml version="1.0" encoding="UTF-8"?>
<foo bar="some foo"/>
<foo bar="some foo"/>
<foo bar="some foo">

      foo</foo>
<foo bar="some foo">

      foo</foo>


> Which seems correct.  What do you get?

This also seems correct to me.

Obviously, the template that I originally showed was not, in fact, the template I was using, it was simply a similar template.

Checking further in my code, I discovered that I had not used a <xsl:output /> element.  I didn't know that I needed that, but without it, my stylesheet doesn't work.

Thanks,
--Brendan


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