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Re: [xsl] knowing the position of certain node


Subject: Re: [xsl] knowing the position of certain node
From: Mukul Gandhi <mukulgandhi2003@xxxxxxxxxxx>
Date: Tue, 6 Jan 2004 13:57:32 +0000 (GMT)

Hi Jaime,
  Please try the following XSL Template ;)

<xsl:template match="/test">
  <xsl:for-each select="row">
     <xsl:if test = "field2 = 'yes'">
         <xsl:value-of select="position()" />
     </xsl:if>
  </xsl:for-each>	
</xsl:template>

Regards,
Mukul

 --- Jaime A Stuardo Bahamondes <jstuardo@xxxxxxxxxxx>
wrote: > Hi all..
> 
> I have this sample XML:
> 
> <test>
>   <row>
>     <field1>this</field1>
>   </row>
>   <row>
>     <field1>is</field1>
>   </row>
>   <row>
>     <field1>a</field1>
>     <field2>yes</field2>
>   </row>
>   <row>
>     <field1>test</field1>
>   </row>
> </test>
> 
> 
> If I use <xsl:value-of select="row[field2 = 'yes']"
> /> I get all the third "row" field values. How can I
> know the position of the found node? for example, in
> that case, I want 3 to be printed on screen,
> something like "position(row[field2 = 'yes'])"
> 
> Thanks
> Jaime
> 
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list
>  

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