Re: [xsl] not having all the children of an element in the output

Hi Toma,
Something like this should work

<xsl:template match="node()|@*">
   <xsl:copy>
   <xsl:apply-templates select="@*"/>
   <xsl:apply-templates/>
   </xsl:copy>
 </xsl:template>
<xsl:template match="term"/>
</xsl:stylesheet>

 This is doing Identity transformation and not telling what to do with the
<term> node..
So you copy everything except the term node.
Do the same to the <note> node If you want the note node to be  left..
hope this helps
Vasu

----- Original Message ----- 
From: "Toma Tasovac" <ttasovac@xxxxxxxxxxxxx>
To: <XSL-List@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, December 30, 2003 4:04 AM
Subject: [xsl] not having all the children of an element in the output


> Hi!  This is a pretty basic question, so I hope you won't mind me
> posting it here.
>
> I have an XML doc which contains certain marked terms and has notes
> attached next to them, like this:
>
> <p>some text <term>some phrase</term><note><term>basic form of the
> phrase><gloss>explanation of the phrase</gloss>some text.</p>
>
> In other words, <p> element can have two children: <term> marking the
> phrase as it appears in the text and being part of the text itslef, and
> <note> which attaches a note explaining the term in some detail.
>
> I am having problems designing an xsl template which will output:
>
> <p>some text<term>some phrase</term>some text</p>
>
> i.e. which will include only one of the two possible children
> elements... Everything I do outputs either both <term> and <note> OR
> neither one of them... What's the trick?
>
> Many thanks in advance,
>
> Toma
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>

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