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[xsl] Re: Re: Can not convert #STRING to a NodeList! Error..

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Thanks Dimitre,
On seeing the process of execution,(in xmlspy), from Default Template, control comes to my third template. I also think the same that default template is not passing anyparameters to my third template.. I am giving my code: minimal possible one.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:key name="label" match="labels/label" use="@name"/>
<!-- parameter to get the current user's language-->
<xsl:param name="language" select="'en'"/>
<xsl:template match="/"> (first)
<xsl:choose>
<xsl:when test="$language='en'">
<xsl:call-template name="main">
<xsl:with-param name="labelsfile" select="document('English.xml')"/>
</xsl:call-template>
</xsl:when>
<xsl:when test="$language='fr'">
<xsl:call-template name="main">
<xsl:with-param name="labelsfile" select="document('French.xml')"/>
</xsl:call-template>
</xsl:when>
</xsl:choose>
</xsl:template>
<xsl:template name="main">(second)
<xsl:param name="labelsfile"/>
<xsl:for-each select="$labelsfile">
<!-- works fine -->
<xsl:value-of select="key('label','ecollab.purchaseorder')"/>
</xsl:for-each>
<xsl:apply-templates>
<xsl:with-param name="labelsfile" select="$labelsfile"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="HEADER">(third)
<xsl:param name="labelsfile"/>
<xsl:for-each select="$labelsfile">
<!-- Doesnt works -->
<xsl:value-of select="key('label','ecollab.businessfollowedby')" />
</xsl:for-each>
</xsl:template>
<xsl:stylesheet>

sample XML
------------------
<PUR-ORD>
<DOCTYPE-ID>PO</DOCTYPE-ID>
<CONTACT>610223</CONTACT>
<!-- value of above nodes are printed by default template -->
<PO>
<HEADER>header information</HEADER>

	</PO>
</PUR-ORD>

What should I do to solve this problem.
thanks in advance
regards
s.arun prasath

From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] Re: Re: Can not convert #STRING to a NodeList! Error..
Date: Sun, 9 Nov 2003 16:43:19 +0100

It seems to me that your description matches completely the guess I made in
my previous message.

If you do value your time it would be best to publish a complete (but the
minimal possible) example, including the xslt code, the source xml document
and where you think the problem happens.

From what you have written:

> 3. From this template, I am again calling child templates using
> <xsl:apply-templates>
> <xsl:with-param name="labelsfile" select="$labelsfile"/>
> </xsl:apply-templates>
> 4. Next Default template prints the node values for some of the xml
> tags.
> 5. Next when a template node is matched (third),the third template is
> being executed, I have declared the param tag
> <xsl:param name="labelsfile"/>
>
> Problem comes only here.. here, the variable "labelsfile" is shown as a
> String rather than a Nodelist. and its value is blank.
> and when the tag <xsl:for-each select="$labelsfile"> is being executed, it
> shows error.

it seems that the "third template" is instantiated from a "default"
template. If this is so, the default template does not use an
"xsl:with-param" when it issues "xsl:apply-templates". If this is so, no
value for any parameter is passed to the "third template" and the xsl:param
named labelsfile does not get any value -- this causes the error message.

=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

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