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Hi,
In my XSL,
from the parent template I load a XML file using document() function. and I pass this as parameter to child templates.
<xsl:call-template name="main">
<xsl:with-param name="labelsfile" select="document('English.xml')"/>
</xsl:call-template>
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[xsl] Can not convert #STRING to a NodeList! Error..
Subject: [xsl] Can not convert #STRING to a NodeList! Error.. From: "arun prasath" <arunwaits@xxxxxxxxxxx> Date: Sat, 08 Nov 2003 21:10:21 +0530 |
Hi,
In my XSL,
from the parent template I load a XML file using document() function. and I pass this as parameter to child templates.
<xsl:call-template name="main">
<xsl:with-param name="labelsfile" select="document('English.xml')"/>
</xsl:call-template>
In my child templates, I am retrieving using <xsl:param name="labelsfile"/>
I also have declared a key(xsl:key) in the importing xml file in my xsl. <xsl:for-each select="$labelsfile"> <xsl:value-of select="key('label','ecollab.businessfollowedby')" /> </xsl:for-each>
when I transform this using my java program, I get the following exception. Can not convert #STRING to a NodeList!
I want to know why we get this error usually. please help regards s.arun prasath
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