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Re: [xsl] Display dates in specific format

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Hi Puja,
You may do, something like --

<xsl:template match="/dataroot/GrantNet">
  <xsl:variable name="year" select="substring(c9, 1,
4)"/>
  <xsl:variable name="month" select="substring(c9, 9,
2)"/>
  <xsl:variable name="day" select="substring(c9, 6,
2)"/>
  <xsl:value-of select="concat($day, '/' , $month,
'/', $year)"/>
</xsl:template>

Regards,
Mukul

--- puja thakral <puja_thakral@xxxxxxxxx> wrote:
> Hi All,
> I've an xml document.
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <dataroot>
> 	<GrantNet>
> 		<c0>0005</c0>
> 		<c1>111</c1>
> 		<c2>GS</c2>
> 		<fldSponsorDesc>American Association
> </fldSponsorDesc>
> 		<Program>2000-2001 American Fellowships</Program>
> 		<URL>http://www.aauw.org/3000/fdnfelgra.html</URL>
> 		<Description></Description>
> 		<c9>1999-11-15T00:00:00</c9>
> 		<c13>Web</c13>
> 		<c14>1999-10-11T00:00:00</c14>
> 		<c15>False</c15>
> 		<c16>AH</c16>
> 		<fldCatDesc>Arts &amp; Humanities</fldCatDesc>
> 	</GrantNet>
> </dataroot>
> 
> I'm using stylesheet to display all the information
> in
> html format.
> But I don't know how to display date.I get the date
> displayed as 1999-11-15T00:00:00 although I want to
> display it as 11/15/1999.
> 
> Thanks for help in advance.
> Regards,
> Puja
> 
> 
> 
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