[XSL-LIST Mailing List Archive Home] [By Thread] [By Date]

RE: [xsl] XML to HTML: How to make decisions based on what has been displayed

---

---

> 
> > This shouldn't matter. position() calculates the position of
> > the current
> > node within the current node list, which is the list of 
> nodes selected
> > using <xsl:apply-templates> or <xsl:for-each>. So long as you 
> > select the
> > nodes to be included using one of those instructions (and not, for
> > example, by selected a larger set of nodes and then 
> selecting a subset
> > using xsl:if or xsl:choose) the position() should be set correctly.
> 
> Thanks for your answer, Michael. Actually, I'm doing exactly what you
> describe: I select a larger set of nodes, then selecting a 
> subset with xsl:if. So we're back to the original question: 
> is there any way to alternate the row color given that 
> position() won't help me much?

Try to restructure it so you select the subset using xsl:for-each.

Instead of 

<xsl:for-each select="x">
  <xsl:if test="c">
    <tr>

do

<xsl:for-each select="x[c]">
  <tr>

> 
> 
> > should be doing something like:
> > 
> > <xsl:value-of select="name(element[.//*[conditions]][1])"/>
> 
> Can you explain more on this? Should "element" stay as such 
> or be replaced with the real name of the element I'm looking 
> for (which turns out to be "Sequence").

This was intended as pseudo-code. Substitute the right things for
"element" and "conditions".

 Also, "conditions" 
> need to contain an "xsl:for-each". Is that possible?

No, it's not possible, but are you really sure it is necessary?

Michael Kay


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

---