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Re: [xsl] Reference problem


Subject: Re: [xsl] Reference problem
From: "belangour abdessamad" <abdessamad.belangour@xxxxxxxxxxxxxxxxxxx>
Date: Mon, 20 Oct 2003 15:45:54 +0200

Hi Jarno,
I have added the namspace with no errors, but the "idref" fields are still
empty. How could we indicate then for the xslt processor to refer elements
from the xml file being generated (types ids) and not the source one on
which it's operating.
thanks again.
----- Original Message ----- 
From: <Jarno.Elovirta@xxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, October 20, 2003 1:11 PM
Subject: RE: [xsl] Reference problem


Hi,

> First of all, thanks of answering me. I have copied your xslt
> program and
> tried to run it, but the xslt processor declares 3 errors
> (for x unknown
> namespace) so i have removed the 'x' and placed the datatypes
> at the start
> of the document (as below) but it does not suceeded. What's

x was just a namespace that I used to be able to embed the mapping elements
into the stylesheets. You need to declare e.g. xmlns:x="x".

> wrong with this.
> Can we simply make a named template (getDaTyID) with a
> parameter  for doing
> the job?.
> Thanks again.
> -----------------------------------------
> <xsl:template match="/">
>     <document>
>         <dataTypes>
>             <dataType id="1" name="string"/>
>             <dataType id="2" name="integer"/>
>            <dataType id="3" name="float"/>
>         </dataTypes>
>         <xsl:apply-templates select="variables"/>
>         </document>
> </xsl:template>
> ----------------------------------------------
> <xsl:template match="var">
>     <xsl:copy>
>       <xsl:apply-templates select="@name"/>
>       <xsl:for-each select="@type">
>         <xsl:element name="{local-name()}">
>           <xsl:attribute name="idref">
>             <xsl:value-of
> select="document('')/*/dataTypes/dataType[@name =

This will not work, as a stylesheet cannot contain elements in
null-namespace. Add the namespace prefix and declare the namespace—makes no
difference what the URI is (as long as it isn't XSLT's namespace URI).

Cheers,

Jarno - DE/VISION: Endlose Traume

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