[XSL-LIST Mailing List Archive Home] [By Thread] [By Date]

Re: [xsl] Copying XML file over using XSLT


Subject: Re: [xsl] Copying XML file over using XSLT
From: Mukul Gandhi <mukulgw3@xxxxxxxxx>
Date: Mon, 13 Oct 2003 23:47:43 -0700 (PDT)

sorry I posted a slightly wrong XSL.. The correct one
is --

<xsl:template match="/">
   <xsl:copy-of select="." />
</xsl:template>

The previous one is also working, but this -- is
better..

Regards,
Mukul

--- Mukul Gandhi <mukulgw3@xxxxxxxxx> wrote:
> Hi Navid,
>  Below is the XSL..
> 
> This is an identity transform --
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> <xsl:output method="xml" version="1.0"
> encoding="UTF-8" indent="yes"/>
> 	
> <xsl:template match="/">
>    <xsl:copy-of select="node() | @*" />
> </xsl:template>
> 
> </xsl:stylesheet>
> 
> Regards,
> Mukul
> 
> --- "Navid M." <navid89@xxxxxxxxx> wrote:
> > Hello,
> > 
> > Is there a short cut for copying all the content
> of
> > my
> > XML file to an XHTML file using XSLT?
> > 
> > i.e. I want to create an XSLT file that will take
> > the
> > content of an XML file and put it in another file
> > exactly as it appears.
> > 
> > Any help would be greatly appreciated.
> > 
> > Thanks,
> >  Navid M.
> > 
> > __________________________________
> > Do you Yahoo!?
> > The New Yahoo! Shopping - with improved product
> > search
> > http://shopping.yahoo.com
> > 
> >  XSL-List info and archive: 
> > http://www.mulberrytech.com/xsl/xsl-list
> > 
> 
> 
> __________________________________
> Do you Yahoo!?
> The New Yahoo! Shopping - with improved product
> search
> http://shopping.yahoo.com
> 
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list
> 


__________________________________
Do you Yahoo!?
The New Yahoo! Shopping - with improved product search
http://shopping.yahoo.com

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



Current Thread
Keywords