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Re: [xsl] Problems doing XSL Transformation using ASP


Subject: Re: [xsl] Problems doing XSL Transformation using ASP
From: Mukul Gandhi <mukulgw3@xxxxxxxxx>
Date: Fri, 10 Oct 2003 19:38:23 -0700 (PDT)

The XSL file you posted, when applied to the XML,
_works fine with MSXML3.0_ . From your code, it looks
to me that you are using MSXML2.0 . MSXML2.0 does not
conform to the official W3C XSL Recommendation. I
guess MSXML2.0 supports the _W3C XSL Working Draft_ . 

But _MSXML3.0 supports W3C XSLT 1.0 and the W3C XPath
1.0 Recommendations_. If you can try with MSXML3.0, I
think the problem will be solved. Or you can try with
MSXML4.0. It also supports W3C Recommendations..

Regards,
Mukul


--- Rangarajan Calyanakoti <crranga@xxxxxxxxxxx>
wrote:
> Folks,
> 
> I have a very simple XML, XSL file and a very simple
> ASP file to perform the 
> XSL Transformation on the XML file using the XSL
> file and providing it to 
> any client browswer.  I get the following error.
> 
> NOTE: If I open the xml file (that is just from the
> client side) it works 
> just fine!
> 
> What am I missing???
> 
> ERROR
> ---------
> 
> msxml3.dll error '80004005'
> 
> The stylesheet does not contain a document element.
> The stylesheet may be 
> empty, or it may not be a well-formed XML document.
> 
> /test/vqtreport.asp, line 9
> 
> 
> ASP FILE - dummy.asp
> ------------
> <%@ language=javascript %>
> <%
>    var xslt = new
> ActiveXObject("Msxml2.XSLTemplate");
>    var xslDoc = new
> ActiveXObject("Msxml2.FreeThreadedDOMDocument");
>    var xslProc;
>    xslDoc.async = false;
>    xslDoc.resolveExternals = false;
>    xslDoc.load("dummy.xsl");
>    xslt.stylesheet = xslDoc;
>    var xmlDoc = new
> ActiveXObject("Msxml2.DOMDocument");
>    xmlDoc.async = false;
>    xmlDoc.resolveExternals = false;
>    xmlDoc.load("dummy.xml");
>    xslProc = xslt.createProcessor();
>    xslProc.input = xmlDoc;
>    xslProc.transform();
>    Response.Write(xslProc.output)
> %>
> 
> 
> XML FILE - dummy.xml
> ------------
> <?xml version="1.0"?>
> <?xml-stylesheet type="text/xsl" href="dummy.xsl"?>
> 
> <DUMMY>
> </DUMMY>
> 
> XSL FILE - dummy.xsl
> ------------
> <?xml version='1.0'?>
> <xsl:stylesheet version="1.0"
>    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>    <xsl:output method="html" indent="yes"/>
> 
>    <xsl:template match="/">
>       <html>
>          <h1>Yahoooooooo</h1>
>       </html>
>    </xsl:template>
> </xsl:stylesheet>
> 
>
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