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RE: [xsl] Date Format in XSLT
Subject: RE: [xsl] Date Format in XSLT From: "Michael Kay" <mhk@xxxxxxxxx> Date: Thu, 4 Sep 2003 15:41:25 +0100 |
If the names are all three characters, use substring("JanFebMarApr....", ($month-1)*3+1, 3) Michael Kay > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > michel geadah > Sent: 04 September 2003 13:47 > To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Date Format in XSLT > > > hi, > > I need to transform the month to words. > For example, if i have '1' i need to output 'Jan', if i have > '2' i need to > output 'Feb', and so on... > (That is to say if i have 1-12-2003 i need it to be transformed to > 1-Dec-2003) > > Thanks... > Michel > > _________________________________________________________________ > Tired of spam? Get advanced junk mail protection with MSN 8. > http://join.msn.com/?page=features/junkmail > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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