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RE: [xsl] substitute with
Subject: RE: [xsl] substitute with <br/> From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 7 Aug 2003 23:54:34 +0100 |
> As DC always says 'the reference and the character are one and the same > thing' - you could write your entire xml file in character references > (if you were mad). Ah, but DC's mother always says "its the exception that proves the rule" In this case the exception is that an explict #13 character will be normalised by the XML parser to a #10 but a &_#13; character reference will be reported as a #13 character. Which is why Markus isn't actually correct to state: > &_#13; cannot be matched or replaced with XSLT functions, as it has > been deleted by the XML parser. if all references to #13 were changed to #10s by the XML parser a template matching .=&_#13; would work as expected (as the stylesheet's xml parser would change it to a test for #10, and it would match newlines in teh source) However the character ref is reported as character 13, and so _probably_) never matches anything in the source. It would not match newlines in the source, but would match explicit &_#13; references. David XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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