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RE: [xsl] Finding last node in recursive tree
Subject: RE: [xsl] Finding last node in recursive tree From: "Michael Kay" <mhk@xxxxxxxxx> Date: Thu, 7 Aug 2003 21:55:42 +0100 |
xsl:if test="not(following::dataset | descendant::dataset)" Michael Kay > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > Woosley, David > Sent: 07 August 2003 20:33 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Finding last node in recursive tree > > > Assume my XML document contains one or MORE hierarchies of > 'dataset' nodes, like this: > > <report> > <stuff/> > <dataset> > <dataset> > <stuff/> > </dataset> > <dataset> > <stuff/> > </dataset> > </dataset> > <stuff/> > <dataset> > <dataset> > <stuff/> > <dataset> > <stuff/> > </dataset> > <DATASET> > <stuff/> > </dataset> > <stuff/> > </dataset> > </dataset> > <stuff/> > </report> > > The 'dataset' levels will vary in depth. Other elements will > be sprinkled among the 'dataset' nodes. How can I determine > when I am at the beginning of the very LAST 'dataset' node > (the node in caps above), regardless if its depth? > > Many thanks, > > David Woosley > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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