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I wnat to create a directory like index from a list of names. I want to have section heading for each existing first-letter, followed by all names starting with that first letter, omitting non-existant letters.
Like this:
I made it this far:
But this is creating an extra list for all names for every letter, that would be three times the list for M in my above example.
Any ideas on altering the code?
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[xsl] creating a directory-like index
Subject: [xsl] creating a directory-like index From: Alexander Czernay <listen@xxxxxxxxxxx> Date: Thu, 07 Aug 2003 15:00:19 +0200 |
I wnat to create a directory like index from a list of names. I want to have section heading for each existing first-letter, followed by all names starting with that first letter, omitting non-existant letters.
Like this:
A Alexander Andrea
M Martin Max Moritz . . .
I made it this far:
<xsl:template match="/"> <xsl:for-each select="artist[substring(name,1,1)]"> <xsl:sort select="name"/> <div class="group"> <h1><xsl:value-of select="substring(name,1,1)"/></h1> <xsl:call-template name="artistlist"> <xsl:with-param name="letter" select="substring(name,1,1)"/> </xsl:call-template> </div> </xsl:template>
<xsl:template name="artistlist"> <xsl:param name="letter"/> <xsl:for-each select="artist[starts-with(name,$letter)]"> <xsl:sort select="name"/> <div class="artist"><xsl:value-of select="name"/></div> </xsl:for-each> </xsl:template>
But this is creating an extra list for all names for every letter, that would be three times the list for M in my above example.
Any ideas on altering the code?
Thanks for your help, Alexander
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