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[xsl] How to construct an XPath expression for this node-set?
Subject: [xsl] How to construct an XPath expression for this node-set? From: Tim Meals <tmeals@xxxxxxxxx> Date: Wed, 6 Aug 2003 15:16:27 -0700 |
I'm working with a problem I'd like to solve with a single XPath expression. Yes, this is slightly off-topic, but I've seen some of the mind-boggling XPath expressions pass through this list and can't figure out how to do this one myself. The XML file excerpt is something like this: ... <Address addressID="100"> <Name xml:lang="en">90 - Test Name</Name> ... </Address> ... <Address addressID="100"> <Name xml:lang="en">91 - Another Name</Name> ... </Address> By definition, there are more than one Address element per XML file. Normally, there will be exactly two, but the spec allows the number to be open-ended. I would like to receive back a nodeset from the XPath expression, but concatenating the addressID with the substring-before(Name, ' '). If I evaluate: concat( //Address/@addressID, '-', substring-before( //Address/Name, ' ' ) ) I get back a String with one value ("100-90", in this case). What I want is a nodeset containing elements with "100-90", "100-91". Does anyone have any ideas on how to procede? I'm running Xalan 2.4.1, but could upgrade to 2.5.1 if there is functionality there that's not present in 2.4.1. Thanks, Tim -- e-mail: tmeals@xxxxxxxxx "Recommend to your children virtue; that alone can make them happy, not gold." -- Ludwig van Beethoven XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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