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[xsl] comparing nodes by name
Subject: [xsl] comparing nodes by name From: Stephan Kahnt <stephan.kahnt@xxxxxxxxxx> Date: Tue, 5 Aug 2003 17:12:46 +0200 |
Hi, I do have the following Problem. I need to find all nodes in a subtree /AAA/BBB that don't have the same name as any name in the current context /AAA/DDD. In the following example this would result to /AAA/BBB/KKK, because it's the only node under /AAA/BBB that does not exist under /AAA/DDD. The problem for me is, that not the nodes or the values of the nodes have to be compared but the names. Does someone out there know how to do this? Thanks in advance. <AAA> <BBB> <CCC>1</CCC> <KKK>2</KKK> </BBB> <DDD> <CCC>2</CCC> <EEE>3</EEE> </DDD> </AAA> Best regards Stephan Kahnt XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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