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AW: [xsl] not working...

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Hello John,

assuming all inputs are descendants of one single
<HSDataContainerType list="true" name="Inputs" ...> and the same for
outputs, consider using three templates instead of one:

<xsl:template match="HSDataContainerType[contains(@name, 'Inputs']">
  <!-- HTML output for "Inputs" heading comes here -->
</xsl:template>

<xsl:template match="HSDataContainerType[contains(@name, 'Outputs']">
  <!-- HTML output for "Outputs" heading comes here -->
</xsl:template>

<xsl:template match="HSDataContainerType">
  <!-- HTML output for fields that are not headings comes here -->
</xsl:template>


Regards,
Markus
__________________________
Markus Abt
Comet Computer GmbH
http://www.comet.de



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Von: 	John Liebermann
Gesendet: 	Samstag, 16. August 2003 00:52
An: 	xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Betreff: 	RE: [xsl] <xsl:for-each> not working...

[...]

I was using a for-each loop with ancestor::* to clearly display the path to
each field. That works perfect. The problem is that i don't process Inputs
and Outputs separetely. They are both of <HSDataContainer> type so i use :
--------------------------------------------
<xsl:template match="HSDataContainerType">
  <xsl:choose>
	<xsl:when test="contains(@name, 'Inputs')">
		<img src="dcopenicon.gif">
		<a href="#in"><b><xsl:value-of select="@name"/></b></a></img>
		<div style="margin-left: 3em;">
		<xsl:apply-templates select="*"/></div>
	</xsl:when>

. exactly the same for 'Outputs'
--------------------------------------------

[...]

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