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Re: [xsl] number continuation problem

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<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"
>


<xsl:template match="node">
.<xsl:value-of select="
1 +
count(preceding-sibling::node) +
count(parent::if/preceding-sibling::if[count(node)&gt;count(following-sibling::*[1][self::else]/node)]/node) +
count(parent::else/preceding-sibling::if[position()&gt;1][count(node)&gt;count(following-sibling::*[1][self::else]/node)]/node) +
count(../preceding-sibling::else[count(node)&gt;=count(preceding-sibling::*[1][self::if]/node)]/node)
"/>.<xsl:value-of select="."/>
</xsl:template>


</xsl:stylesheet>


> Now, if you make it handle nested if/else's within nodes that would be
> special :)

depends how you want them to be counted. Since the code above only uses
sibling and parent axes, not following or ancestor for example, it is
naturally scoped to the parent of your sibling if and else nodes.
So you should be able to make 1.2.3 style numbering easily enough.
If however you actually want a continuous decimal numbering across nodes of
arbitrary depth then more or less you would need to change
preceding-sibling to preceding, and er, then change whatever else needs
changing to what it needs changing to.

David

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