[XSL-LIST Mailing List Archive Home] [By Thread] [By Date]

RE: [xsl] obtaining name of output file


Subject: RE: [xsl] obtaining name of output file
From: "Michael Kay" <mhk@xxxxxxxxx>
Date: Wed, 7 May 2003 20:56:45 +0100

> Hi,
> 
> I need to obtain the name of the output file as specified at 
> the command line of the XSLT-processor. Is there a way to do this?
> 

Pass it in as a parameter. (Write a simple shell script that uses the
same value for the output file and the value of the xxxoutput-file
stylesheet parameter.)

Michael Kay


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



Current Thread