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[xsl] obtaining name of output file
Subject: [xsl] obtaining name of output file From: "Daniel Brauer" <daniel.brauer@xxxxxxxxxxxxx> Date: Wed, 7 May 2003 16:50:32 +0200 |
Hi, I need to obtain the name of the output file as specified at the command line of the XSLT-processor. Is there a way to do this? Thanks Daniel. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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