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RE: [xsl] Vertical display

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> How this link solves the current problem?
>
> thanks,
> sundar
> 
> -----Original Message-----
> From: Dimitre Novatchev [mailto:dnovatchev@xxxxxxxxx]
> Sent: Monday, April 28, 2003 5:50 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] Vertical display 
> 
> See:
> 
> http://groups.google.com/groups?dq=&hl=en&lr=&ie=UTF-8&oe=UTF-
> 8&selm=b8ftqh%
> 249iaui%241%40ID-152440.news.dfncis.de&rnum=4


By providing a generic templates that produce a column-first HTML table
from the nodes of a node-set. The node-set and the desired number of
columns are provided as parameters.

In your case you will call this template like this:

  <xsl:variable name="numCols" select="count(/o/com/*[1]/*)" />

  <xsl:template match="/">
    <table>
      <xsl:apply-templates mode="multiColumn"
       select="(/o/com/*/*)[position() &lt;= $numCols]">
        <xsl:with-param name="numCols" select="$numCols" />
        <xsl:with-param name="nodes" select="/o/com/*/*" />

       </xsl:apply-templates>
    </table>
  </xsl:template>

This produces the wanted result:

<table>
  <tr>
    <td>1</td>
    <td>4</td>
    <td>41</td>
    <td>42</td>
  </tr>
  <tr>
    <td>2</td>
    <td>5</td>
    <td>51</td>
    <td>52</td>
  </tr>
  <tr>
    <td>3</td>
    <td>6</td>
    <td>61</td>
    <td>62</td>
  </tr>
</table>





=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

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