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Re: [xsl] Using an index with a sorted list of elements
Subject: Re: [xsl] Using an index with a sorted list of elements From: bix_xslt@xxxxxxxxxxx Date: Wed, 19 Mar 2003 00:56:39 -0600 |
Hugh, > I have a number of elements, similar to <element @value/> > I want to find the element that has the biggest value of "value" less > than a value $upperBound. I would try to think about it more like this. Let me sort the values first, and then grab the value I want (i.e. small easy steps will get me there sooner). <x:for-each select="//*[@value < $upperBound]"> <x:sort data-type="number" order="descending" select="@value"/> <x:if test="position() = 1"><x:value-of select="@value"/></x:if> </x:for-each> To break it down, this selects every node that has a @value less than the upper bound, and then sorts based on that value attribute in a descending order. Then, it selects the first one. There's probably another, slicker way to do this with the [1], but I think this will work for you. bix XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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