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Re: [xsl] Transforming XML to HTML Table
Subject: Re: [xsl] Transforming XML to HTML Table
From: Oleg Tkachenko <olegt@xxxxxxxxxxxxx>
Date: Wed, 29 Jan 2003 14:59:56 +0200
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Nick Foster wrote:
but I only got the value of the first sample in all columns. Is there a
way of looping through the $columntitles/labels and selecting the sample
where the label matches in the current row?
Try
<xsl:for-each select="$columntitles">
<TD>
<xsl:value-of select="$samples[label=current()/label]/displayval"/>
</TD>
</xsl:for-each>
But what's order? You've got "sample 1" in first row and "Sample 1" in the
second one. Is this a typo?
--
Oleg Tkachenko
eXperanto team
Multiconn Technologies, Israel
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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