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RE: [xsl] value of variable inside a condition doesn't work?
Subject: RE: [xsl] value of variable inside a condition doesn't work? From: cknell@xxxxxxxxxx Date: Tue, 28 Jan 2003 14:55:15 -0500 |
> -----Original Message----- > From: "Hubert Holtz" <Turnhose_alt@xxxxxxx> > > <xsl:if test="($lang)='1' "> > <xsl:variable name="stadt" select="Stadt"/> > <xsl:variable name="Texteingabe" select="Hier Text eingeben"/> > <xsl:variable name="berichtstatus" select="aktuell"/> > </xsl:if> > > <xsl:if test="($lang)='2' "> > <xsl:variable name="stadt" select="city"/> > <xsl:variable name="Texteingabe" select="Please enter text"/> > <xsl:variable name="berichtstatus" select="current"/> > </xsl:if> > > .. > > <td><xsl:value-of select="$stadt"/></td> > > -- code -- You have two problems: 1) When you assign a literal string to a variable, you must doubly quote the string, thus: <xsl:variable name="stadt" select="'city'"/> not as you have done: <xsl:variable name="stadt" select="city"/> 2) A variable exists only within the scope where it was defined. Once you exit that scope (in your example, once the transformation exits the <xsl:if> element) the variable ceases to exist. You have two choices here: 2a) Put all the relevant templates and elements inside each <xsl:if> element. 2b) Define the templates once and invoke them inside each <xsl:if> by using <xsl:apply-templates> or <xsl:call-template>. -- Charles Knell cknell@xxxxxxxxxx - email XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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