[XSL-LIST Mailing List Archive Home]
[By Thread]
[By Date]
I have N streams of "input" XML (N > 1), to be transformed into M streams of "output" XML (M > 1, M != N).The transformation is complex in that data from several input streams might be required to construct a single output element.
What is the best strategy for this? I cannot transform the N input streams on a one-by-one basis as it seems. I can merge all N input streams into a single input streams (maybe with the aid of seperate namespaces), but will a single transformation, applied to a single input stream, allow for the creation of multiple output documents simultaneously?
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
[xsl] N : M transformation
Subject: [xsl] N : M transformation From: Bernd Gauweiler <bernd@xxxxxxxxxxxxx> Date: Tue, 28 Jan 2003 08:10:49 -0800 |
I have N streams of "input" XML (N > 1), to be transformed into M streams of "output" XML (M > 1, M != N).The transformation is complex in that data from several input streams might be required to construct a single output element.
What is the best strategy for this? I cannot transform the N input streams on a one-by-one basis as it seems. I can merge all N input streams into a single input streams (maybe with the aid of seperate namespaces), but will a single transformation, applied to a single input stream, allow for the creation of multiple output documents simultaneously?
Puzzled. Any advise welcome. Bernd
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] Crane Softwrights Ltd. XSL Tr, G. Ken Holman | Thread | Re: [xsl] N : M transformation, J.Pietschmann |
RE: [xsl] Need advise on filtering , cknell | Date | Re: [xsl] sax or dom in XSLT proces, Johannes Döbler |
Month |