RE: [xsl] XML reformatting

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Subject: RE: [xsl] XML reformatting <xsl:element & <xsl:for-each From: Jarno.Elovirta@xxxxxxxxx Date: Tue, 7 Jan 2003 16:25:53 +0200

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Hi,

> I have an xml file below that needs to be transformed before I can use
> it, the problem is that in the <Table> section there may be more
> parameters later on, this file is coming from a database. 
> 
> I'm trying to use the <xsl:element> in the template for the <Table>
> section and loop through all the child nodes of <Table> to put them in
> the output xml, but It keeps saying that the element name is not a
> QName, How can I accomplish this???
> 
> I'm also getting Odd errors about <xsl:text>, 'Unexpected  Child'.
> 
> Must say thanks to Joerg Heinicke for his insight on my previous
> question, had spent ages on trying to get that working 
> yesterday, seems
> so simple now :), hindsight :)
> 
> 
> 
> Xslt:
> <xsl:template match="Table">
> 	<xsl:for-each select="*">
> 	<xsl:text>
> 		<xsl:value-of select="current()/text()"/>
> 	</xsl:text>

xsl:text can only have character data children. If you don't need the whitespace, just remove the xsl:text element.

> 		<xsl:element name="name()">

The generated element name would be "name()", which isn't a QName. Use AVTs, i.e.

  <xsl:element name="{name()}">

Cheers,

Jarno - Grendel: End of Ages (Arzt+Pfusch Japscat Remix)

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

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RE: [xsl] XML reformatting <xsl:element & <xsl:for-each Jarno . Elovirta - Tue, 7 Jan 2003 16:25:53 +0200 <=

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