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Re: [xsl] Filtering Problem using position()
Subject: Re: [xsl] Filtering Problem using position() From: David Carlisle <davidc@xxxxxxxxx> Date: Fri, 8 Nov 2002 17:15:06 GMT |
> it seems that it is applying the calculation of the position() toto > INCLUDE those rows that I had excluded when I did a template match. yes position() is the position in the current node list ie the nodes slected by the active apply-templates. in your case that is <xsl:apply-templates select="node()|@*"/> so teh current node list will be (first) all attribute nodes (then) all text, element, comment etc nodes, in order. position() will reflect the position of each node matched in this list. so, don't do this <xsl:template match="table[2]/tr[td[not(a) and not(@class)]]"> do this <xsl:template match="table[2]"> <xsl:copy> <xsl:apply-templates select="tr[td[not(a) and not(@class)]|@*"/> </xsl:copy> </xsl:template> now the apply templates from that table will just apply templates to a list of filtered tr nodes, so position() in teh template will do the right thing. David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Scanning Service. For further information visit http://www.star.net.uk/stats.asp or alternatively call Star Internet for details on the Virus Scanning Service. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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