Re: [xsl] Building tables with optional data elements

I have managed to build a list of column names from each row, but I have not
managed to place the correct data in the correct column when a previous
column is missing. i.e. put a blank entry when the column is missing. 
How do I do this? 


<xsl:template match="Item">
<mtr>
<xsl:for-each select="$columns">
<mtd>
<xsl;apply-templates select="NameValue[Name=current()]"/>
</mtd>
</xsl:for-each>
</mtr>
</mtd>
</xsl:template>

where columns is a list of column names defined as appropriate, perhaphs
by

<xsl:variable name="columns" select="document('')/*/x:columns/x:Name"/>

<x:columns xmlns:x="data:,x">
<x:Name>Col1</x:Name>
....

David

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