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Re: [xsl] Re: Selecting a random node from source-tree
Subject: Re: [xsl] Re: Selecting a random node from source-tree From: "Martin Lormes" <martin.lormes@xxxxxxx> Date: Thu, 26 Sep 2002 18:12:07 +0200 |
----- Original Message ----- From: "Dimitre Novatchev" dnovatchev at yahoo dot com To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Thursday, September 26, 2002 5:11 PM Subject: [xsl] Re: Selecting a random node from source-tree > > I was thinking of an XPath expression like this: > > > > document('funnies.xml')/funnies/quote[random()] > > > > Can I avoid using extension elements? > > Yes, use the "randNext" template from FXSL. > > More information is contained in the article: > > "Casting the Dice with FXSL: Random Number Generation Functions in > XSLT" > > http://fxsl.sourceforge.net > /articles/Random/Casting%20the%20Dice%20with%20FXSL-htm.htm > > Hope this helped. Thanks, Dimitre. Awsome article! Unfortunately I always get the same random number (which makes perfect sense, since I can't dynamically generate a starting number :-( ) So I must add this as a condition to my original question: the stylesheet is static. No way of changing that. Thanks for your help. Martin Lormes XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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