[XSL-LIST Mailing List Archive Home] [By Thread] [By Date]

Re: [xsl] Problem regarding getting complete Node with value


Subject: Re: [xsl] Problem regarding getting complete Node with value
From: "Vasu Chakkera" <vasucv@xxxxxxxxxxx>
Date: Wed, 28 Aug 2002 07:31:22 +0000

Mukul,
the following code will help you

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"
xmlns:java="http://xml.apache.org/xslt/java"
exclude-result-prefixes="java">
<xsl:output method="xml" indent="yes"/>
<xsl:output encoding="ISO-8859-1"/>
<xsl:template match="DataSet">
<AccountDetails>
<xsl:copy-of select="node()"/>
</AccountDetails>
</xsl:template>
</xsl:stylesheet>

cheers
Vasu

From: Mukul.Mudgal@xxxxxxxxxxx
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] Problem regarding getting complete Node with value
Date: Wed, 28 Aug 2002 12:04:44 +0530

Hi friends

I'm try to convert this

<DataSet XslFileName="AccountOpen.xsl">
      <SortCode Value="000002"/>
      <AccountNumber Value="123456789"/>
      <BranchCodeOrig Value="127"/>
      <ProductCode Value="101010"/>
      <JointMandate Value = "E"/>
      <OpenDate Value="0020730"/>
      <ACCRINTDATELAST Value="20020730" />
      <Balance Value="10"/>
</DataSet>

in to this
<AccountDetails>
      <SortCode Value="000002"/>
      <AccountNumber Value="123456789"/>
      <BranchCodeOrig Value="127"/>
      <ProductCode Value="101010"/>
      <JointMandate Value = "E"/>
      <OpenDate Value="0020730"/>
      <ACCRINTDATELAST Value="20020730" />
      <Balance Value="10"/>
</AccountDetails>

I'm using this xsl file

<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0"
xmlns:java="http://xml.apache.org/xslt/java"
exclude-result-prefixes="java">
<xsl:output method="xml" indent="yes"/>
<xsl:output encoding="ISO-8859-1"/>
<xsl:strip-space elements="*"/>
<xsl:template match="*">
            <AccountDetails>
<xsl:copy-of select="DataSet" />
      </AccountDetails>
      </xsl:template>
</xsl:stylesheet>

But after transformation it gives

<?xml version="1.0" encoding="ISO-8859-1"?>
<AccountDetails>
    <DataSet XslFileName="AccountOpen.xsl">
      <SortCode Value="000002"/>
      <AccountNumber Value="123456789"/>
      <BranchCodeOrig Value="127"/>
      <ProductCode Value="101010"/>
      <JointMandate Value="E"/>
      <OpenDate Value="0020730"/>
      <ACCRINTDATELAST Value="20020730"/>
      <Balance Value="10"/>
</DataSet>
</AccountDetails>

though above result is correct but I don't want the <DataSet/>  node. As
I've mentioned above in the required result file.

how could I get the required result,?? Please help....

Thanks
Mukul





XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list




_________________________________________________________________
MSN Photos is the easiest way to share and print your photos: http://photos.msn.com/support/worldwide.aspx



XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list




Current Thread
Keywords
xsl