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[xsl] sorting union results
Subject: [xsl] sorting union results From: Doug Howell <doug@xxxxxxxxxxxxxxxxxxxx> Date: Thu, 15 Aug 2002 13:09:49 -0400 |
Hi, all, Given a structure like this: <glossary> <entry> <term></term> <acronym></acronym> <definition></definition> </entry> </glossary> I'd like my stylesheet to create a list of glossary terms, inserting the acronyms (as if they were terms) where they fit alphabetically in the list. I'd like to avoid having to create another entry for each acronym and keep the XML document smaller.) I tried this: <xsl:for-each select="//term|//acronym"> <xsl:sort select="." order="ascending"/> <p><xsl:value-of select="."/>:</p> </xsl:for-each> This lists the terms and acronyms together, but doesn't sort them (they come out in document order). I think I've read that the union operator can only deliver the selected nodes in document order. Is there any workaround to do what I want to do without creating an intermediary document? Thanks! Doug Howell Information Architect Borders Group Inc. XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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