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RE: [xsl] The longest node in a node set
Subject: RE: [xsl] The longest node in a node set From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Date: Fri, 19 Jul 2002 10:48:46 +0100 |
To add to Jeni's reply: In XPath 2.0, the way you do this is: max(for $n in $nodeset return string-length($n)) In Saxon 6.5.x, you can do it with an extension function: saxon:max($nodeset, saxon:expr('string-length(.)')) (Both of these give you the length of the longest node, not the node itself) But for pure XSLT 1.0/XPath 1.0, Jeni has given you the answer. Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx > -----Original Message----- > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of > Antonio Fiol Bonnin > Sent: 18 July 2002 19:05 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] The longest node in a node set > > > Hello, > > I am trying to find an XPath expression that gives me the longest > element in a node set. > > I know how to do that for an attribute. e.g //element[not(@attr < > following-sibling::element/@attr)] > > But how can I do that for the string-length(element). > > I tried //element[not(string-length(.) < > string-length(following-sibling::element))] > > But this obviously does not work, because > following-sibling::element is > not an element or string, but a node-set. > > Any ideas? > > (I think this one is for Michael Kay... Am I wrong?) > > Thank you very much. > > > Antonio Fiol > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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