[XSL-LIST Mailing List Archive Home]
[By Thread]
[By Date]
RE: RE: [xsl] Forming a Tree
Subject: RE: RE: [xsl] Forming a Tree From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Date: Fri, 12 Jul 2002 18:04:01 +0100 |
> Hi Michael, > Thanks for the response. I am new to XSL and I never used xsl:key, > could you pl help me, how to write the xsl:key for > <xsl:for-each select="//row[@ParentTopicId=@TopicId and > @BookId=$node1/@BookId and @TopicTitle]">. In xsl:for-each i > am using a variable, i am not getting how to > write xsl:key. > The variable part of that expression is @BookId. So <xsl:key name="k" match="row[@ParentTopicId=@TopicId and @TopicTitle]" use="@BookId"/> then <xsl:for-each select="key('k', $node1/@BookId)"> The key indexes all the rows that satisfy the "fixed" conditions by the value of their @BookId. The select expression finds entries in that index by supplying the required BookId. Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: RE: [xsl] Forming a Tree, Venkatesh Sutrave | Thread | [xsl] regarding newline, subbu |
Re: [xsl] Escaping single quote, David Carlisle | Date | RE: [xsl] XSLT & SQL, Americo Albuquerque |
Month |
Keywords