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Does this help??
http://sources.redhat.com/ml/xsl-list/2002-05/msg01261.html
Joerg
KUMAR NINGASHETTY wrote:
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Re: [xsl] Distinct Grouping and filtering
Subject: Re: [xsl] Distinct Grouping and filtering From: Joerg Heinicke <joerg.heinicke@xxxxxx> Date: Tue, 28 May 2002 23:01:25 +0200 |
Does this help??
http://sources.redhat.com/ml/xsl-list/2002-05/msg01261.html
Joerg
KUMAR NINGASHETTY wrote:
Hi,
In the following xml i need to group by "reg_name" as the outer group and then groupby "stateid" at the next level
Basically need to group applicants whose stateid belonging to same region .Within which only distinct stateid should be picked .Duplicate stateid belonging to same region need to be filtered.
I did try using Keys and preceeding sibling comparision approach .But i guess i didnt do it right ...ANy pointers .
Result looks like : ―---------------------- Reg1 GA <some row of data> PA <some row of data> Reg2 NY <some row of data> VA <some row of data> Reg3 NY <some row of data> GA <some row of data>
Source XML is : ―--------------------
<stream>
<rep>
<states>
<region id="111">
<reg_name>Reg1</reg_name>
<region>
<region id="333">
<reg_name>Reg3</reg_name>
<region> <region id="222">
<reg_name>Reg2</reg_name>
<region> </states>
<apps> <applicant idref="111" statid="GA">
<company>xxx</company>
<amount>2200</amount>
</applicant>
<applicant idref="333" statid="NY">
<company>yyyy</company>
<amount>3200</amount> </applicant>
<applicant idref="333" statid="GA">
<company>zz</company>
<amount>4200</amount> </applicant>
<applicant idref="222" statid="NY">
<company>pp</company>
<amount>5200</amount> </applicant> <applicant idref="222" statid="VA">
<company>qq</company>
<amount>6200</amount> </applicant> <applicant idref="111" statid="GA">
<company>rr</company>
<amount>7200</amount>
</applicant>
<applicant idref="111" statid="PA">
<company>ss</company>
<amount>8200</amount>
</applicant> </apps>
</rep>
</stream>
THanks for your time -Kum
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