[XSL-LIST Mailing List Archive Home]
[By Thread]
[By Date]
Re: [xsl] Transformation in NetScape 6.2 Browser
Subject: Re: [xsl] Transformation in NetScape 6.2 Browser From: "Roma Yankin" <polfin@xxxxxxxx> Date: Wed, 8 May 2002 23:58:31 +0400 |
Hi Pundalik, Actually there is no difference in transforming xml documents both for IE6 and NS6. However you might be using transformNode() method from JS which is implemented only in IEs with MSXML 3 and higher installed. Anyway check out this code that makes simplest trasformation of an xml tree. XML file: ~~~~~~~~~~~~~~~~~~~~~~~~~~~ <?xml-stylesheet type="text/xsl" href="xsl.xsl"?> <sample> <hasattrib hasit="true"> I have attribute </hasattrib> <ihave hasit="candy"> I have attribute </ihave> <noattribute> Nothing here </noattribute> <mychildhave> <child hasit="toy"/> </mychildhave> </sample> XSL file: ~~~~~~~~~~~~~~~~~~~~~~~~~~~ <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="html"/> <xsl:template match="/"> <html> <body> <xsl:for-each select=".//*"> <xsl:if test="@hasit"> <b><xsl:value-of select="name()"/></b> have "hasit" attribute set to <b><xsl:value-of select="@hasit"/></b> <br/> </xsl:if> </xsl:for-each> </body> </html> </xsl:template> </xsl:stylesheet> This will work both in IE and NS, ---- regards Roman! XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Transformation in NetScap, Oleg Tkachenko | Thread | RE: [xsl] Transformation in NetScap, Stuart Celarier |
Re: [xsl] XSLT/XPath 2.0 (was "Iden, Wendell Piez | Date | Re: [xsl] xsl Date Sorting referenc, KUMAR NINGASHETTY |
Month |