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Re: [xsl] sorting date prob


Subject: Re: [xsl] sorting date prob
From: "Joerg Heinicke" <joerg.heinicke@xxxxxx>
Date: Thu, 11 Apr 2002 08:49:29 +0200

Hello Jarkko,

you must bring the date to the format yyyymmdd. The best to do this is in
the XML, because the date-formatting is a style-question, so it should be
done in the stylesheet. If this is not possible, you can do it temporarily
in the stylesheet too:

<xsl:sort select="concat(substring(Time,7,2), substring(Time,4,2),
substring(1,2))"/>

Regards,

Joerg

> Hi!
>
> First things first. Thanks a lot Jeni for your advices about
> selecting attribute for link value.
>
> Then another question:
> I should sort the xml file ascending by the given date.
> The xml syntax is like this:
>
> <Information>
>     <Time>06/04/02</Time> #format is dd/mm/yy
>     <Size>299</Size>
>     <Sender>Moilanen Jarkko</Sender>
>     <Subject id="00223322334342">Xalan</Subject>
> </Information>
>
> <Information>
>     <Time>05/11/02</Time>
>     <Size>45</Size>
>     <Sender>Moilanen Jarkko</Sender>
>     <Subject id="00223322342334342">Atribuutit linkkeina</Subject>
> </Information>
>
> If I try to sort them by xsl:
> <xsl:sort order="ascending" select="Time" />
>
> the result is not the correct one.Is there some solution to this,
> or should the xml file be different concerning the syntax?


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