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RE: [xsl] TIME-PROG
Subject: RE: [xsl] TIME-PROG From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx> Date: Mon, 4 Mar 2002 17:50:14 -0000 |
> I want the out put to be classified according to the logic that > programs shown between 6:00 am and 3:00pm are to be shown on the > first half of the HTML page and the program shown after 3:00 pm > to morning 6:00 am should be shown on the second half of the > page.. Select groups as appropriate: <first-half-of-page> <xsl:apply-templates select="prog[((substring-before(time, ':') + translate('pm', 'apm', '06')*2 + 18) mod 24) <= 9]"/> </first-half-of-page> <second-half-of-page> <xsl:apply-templates select="prog[((substring-before(time, ':') + translate(ampm, 'apm', '06')*2 + 18) mod 24) > 9]"/> </second-half-of-page> This works as follows: First calculate a normalized time hour = substring-before(time, ':') + (if pm then 12 else 0) Get the hours into line: xhour = (hour + 18) mod 24 The use of translate() is completely wacky, but XPath 1.0 has no conditional expression so such horrible tricks are quite handy. It turns "am" into "0" and "pm" into 6, then multiplies by 2. not tested. Michael Kay Software AG home: Michael.H.Kay@xxxxxxxxxxxx work: Michael.Kay@xxxxxxxxxxxxxx > > example : this should be the output > > 03:00 am - morning prog1 > 07:00 am - morning prog5 > > <hr></hr> > > 5:30 pm evening prog6 > 6:00 pm evening prog2 > 10:00 pm evening prog3 > 12:30 pm evening prog4 > > Also note that the output programs are in the increasing order of > the time.. > > Can someone help me regarding how i can solve this problem???? > > Many Thanks > > > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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