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[xsl] Can I take only parts from node value?
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Subject: [xsl] Can I take only parts from node value? From: "jp" <jp@xxxxxxxxxxxxxxx> Date: Tue, 19 Feb 2002 16:58:28 +0100 |
Hi, If I have XML-tag like this: <today date="200202190800" /> and I want output: Time is 08:00 Date is 19.02 Year is 2002 How can I do this with XSL/T? Or should I change XML output? Regs, -JP XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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